SOLUTION: If set R consists of 5 letters and set S consists of 3 numbers, then how many elements are in the union of the two sets? OPTIONS: 0 2 3 5 8

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: If set R consists of 5 letters and set S consists of 3 numbers, then how many elements are in the union of the two sets? OPTIONS: 0 2 3 5 8      Log On


   



Question 955751: If set R consists of 5 letters and set S consists of 3 numbers, then how many elements are in the union of the two sets?
OPTIONS:
0
2

3
5
8

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Since there are no elements in common, you just add the elements in
each set.  5+3=8

[If there had been any elements in common, if you added them
you'd be counting the common elkements twice so you'd have
to subtract that number from the sum, but in this case there
are no common elements, so you don't have to subtract anything
from the sum.  The answer is just 5+3=8]

Edwin