Question 955637: Train A left Miami at 5 p.m. heading towards Stuart at the constant rate of 30 miles per hour. At the same time, Train B left Stuart heading towards Miami at the constant rate of 10 miles per hour. The trains traveled on separate, parallel tracks for the 90 miles that separate the two cities. What time did the trains pass each other?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Train A left Miami at 5 p.m. heading towards Stuart at the constant rate of 30 miles per hour.
At the same time, Train B left Stuart heading towards Miami at the constant rate of 10 miles per hour.
The trains traveled on separate, parallel tracks for the 90 miles that separate the two cities.
What time did the trains pass each other?
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let t = the travel time of the two trains when they meet
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When they meet, we know the sum of the distance each traveled equals 90 mi
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Write a distance equation; dist = speed * time
30t + 10t = 90
40t = 90
t = 90/40
t = 2.25 hrs, which is 2 hrs, 15 min
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5:00 + 2:15 = 7:15 is the time the two trains meet
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Confirm this, find the actual distance each train traveled
30 * 2.25 = 67.5 mi
10 * 2.25 = 22.5 mi
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total dist: 90 mi
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