SOLUTION: How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed (remember that you can not have zero as the first digit)?

Algebra ->  sets and operations -> SOLUTION: How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed (remember that you can not have zero as the first digit)?      Log On


   



Question 955574: How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed (remember that you can not have zero as the first digit)?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

if 0 allowed as a starting digit, we have
000000 to 999999 --> 1 million combinations
However, if you disallow 0 as a starting digit then you have the following:
9 choices for the first digit (1-9)
10 choices for the second digit (0-9)
10 choices for the third digit (0-9)
10 choices for the fourth digit (0-9)
10 choices for the fifth digit (0-9)
10 choices for the sixth digit (0-9)
9+%2A+10+%2A+10+%2A+10+%2A+10+%2A10+=+900000+ combinations