Question 955460: The sequence log2 32, log2 y, log2 128, ... forms an arithmetic sequence. What is the value of y?
(note: the number 2 after the log is the subscript)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The sequence log2 32, log2 y, log2 128, ... forms an arithmetic sequence. What is the value of y?
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log2(y)-log2(32) = log2(128)-log2(y)
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log2(y) - 5 = 7 - log2(y)
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2log2(y) = 12
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log2(y^2) = 12
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y^2 = 2^12
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y = 2^6
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y = 64
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Cheers,
Stan H.
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