Question 955412: Given a committee of 8 women and 11 men, how many different ways are there to pick a female president, a male treasurer, and a secretary of either gender if one of the men, Pete, says that he cannot be the treasurer? Assume that none can hold more than one office
Found 2 solutions by hemu_da, stanbon:
Answer by hemu_da(13)   (Show Source):
You can put this solution on YOUR website! .
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No of women = 8
No of men = 11
Total members =19
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1- No of ways selecting 1 woman for female president out of 8 = 8C1 = 8
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2- because one man Pete can not be a treasurer hence the treasurer will be select from remaining 10, i.e.-
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No of ways selecting 1 treasurer out of 10 = 10C1 = 10.
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3- Pete can be a secretary. because none can hold more then one office therefore selection will be done by choosing 1 person out of 7 women and 10 men i.e.-
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No of ways selecting 1 person out of 17 = 17C1 = 17
Total no of ways= 8*10*17 = 1380 .. .. ANS
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! Given a committee of 8 women and 11 men, how many different ways are there to pick a female president, a male treasurer, and a secretary of either gender if one of the men, Pete, says that he cannot be the treasurer? Assume that none can hold more than one office
President: 8 ways
treasurer: 10 ways
secretary: (7+10) = 17 ways
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Ans: 8*10*17 = 1360 ways
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cheers,
Stan H.
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