SOLUTION: two planes, which are 1770 miles apart, fly toward each other. Their speed differ by 40mph. If they pass each other in 3hours, what is the speed of each?
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Question 955380: two planes, which are 1770 miles apart, fly toward each other. Their speed differ by 40mph. If they pass each other in 3hours, what is the speed of each? Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! 1770mi/3hours=590 mph The combined speed is 590mph
r=rate of slower plane; r+40mph=rate of faster plane
r+(r+40mph}=590mph Subtract 40mph from each side.
2r=550 Divide each side by 2.
r=275 ANSWER 1: The slower plane was traveling 275 miles per hour.
r+40mph=275mph+40mph=315 mph ANSWER 2: the faster plane was traveling 315 miles per hour.
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