SOLUTION: If the point (-8,-6) is on the terminal arm of angle A in standard position, then cos(A) is?
a. -4/5
b. -3/5
c. 3/5
d. 4/5
Thank you
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-> SOLUTION: If the point (-8,-6) is on the terminal arm of angle A in standard position, then cos(A) is?
a. -4/5
b. -3/5
c. 3/5
d. 4/5
Thank you
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Question 955374: If the point (-8,-6) is on the terminal arm of angle A in standard position, then cos(A) is?
a. -4/5
b. -3/5
c. 3/5
d. 4/5
Thank you Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! If the point (-8,-6) is on the terminal arm of angle A in standard position, then cos(A) is?
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cos(A) = x/r = -8/sqrt[8^2+6^2] = -8/sqrt(100) = -8/10 = -4/5
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Cheers,
Stan H.
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a. -4/5
b. -3/5
c. 3/5
d. 4/5
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