SOLUTION: A person's phone requires 5 digit password. How many passwords are possible if the 4th digit must be an odd number and the 5th digit must be an even number?
Algebra ->
Probability-and-statistics
-> SOLUTION: A person's phone requires 5 digit password. How many passwords are possible if the 4th digit must be an odd number and the 5th digit must be an even number?
Log On
Question 955368: A person's phone requires 5 digit password. How many passwords are possible if the 4th digit must be an odd number and the 5th digit must be an even number? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! even digits are: 0,2,4,6, and 8
odd digits are: 1,3,5,7,and 9
1st digit: possible
2nd digit: possible
3rd digit: possible
4th digit: possible
5th digit: possible
------------------------
Possible passwords =