SOLUTION: A person's phone requires 5 digit password. How many passwords are possible if the 4th digit must be an odd number and the 5th digit must be an even number?

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Question 955368: A person's phone requires 5 digit password. How many passwords are possible if the 4th digit must be an odd number and the 5th digit must be an even number?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
even digits are: 0,2,4,6, and 8
odd digits are: 1,3,5,7,and 9
1st digit: +10+ possible
2nd digit: +10+ possible
3rd digit: +10+ possible
4th digit: +5+ possible
5th digit: +5+ possible
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Possible passwords = +10%5E3%2A5%5E2+=+25000+