SOLUTION: Write an equation of a line perpendicular to y = x - 5 in slope-intercept form that passes through the point (2, -7).

Algebra ->  Statistics  -> Linear-regression -> SOLUTION: Write an equation of a line perpendicular to y = x - 5 in slope-intercept form that passes through the point (2, -7).      Log On


   

Question 955070: Write an equation of a line perpendicular to y =
x - 5 in slope-intercept form that passes through the point (2, -7).
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The slope for the perpendicular line will be m=-1.

y=mx%2Bb
b=y-mx
What will be b?
b=-7-%28-1%292
b=-6

highlight%28y=-x-6%29

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
Write an equation of a line perpendicular to y =
x - 5 in slope-intercept form that passes through the point (2, -7).
y = x - 5, with slope, or m of 1

Slope of equation of line that's perpendicular to line with equation: y = x - 5: -+1

With m, or slope being - 1, and point (2, - 7), using the point-slope formula: y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29,

we get: y+-+-+7+=+-+1%28x+-+2%29

y + 7 = - x + 2

y = - x + 2 - 7

Equation: highlight_green%28y+=+-+x+-+5%29