SOLUTION: A horse runs along the road. Its distance from the lamp post P on the side of the road is measured at different times, t, and has the form d(t)=at^2+bt+5 The distances are recorde

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A horse runs along the road. Its distance from the lamp post P on the side of the road is measured at different times, t, and has the form d(t)=at^2+bt+5 The distances are recorde      Log On


   



Question 955017: A horse runs along the road. Its distance from the lamp post P on the side of the road is measured at different times, t, and has the form d(t)=at^2+bt+5
The distances are recorded in the table below:
Time(in seconds) 1 2 3 4 5 6
Distance(meters) 10 17 g 37 h 65
So 1 corresponds with 10 and 2 with 17 and so forth.
Determine the values of a and b, for d(t)=at^2+bt+5
(1) a=1 and b=4
(2) a=19/3 (6.33333..) and b=-4/3 (-1.33333..)
(3) a=-9 and b=24
(4) a=6 and b=-1
(5) or none of the above

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
(1,10)
10=a%281%29%5E2%2Bb%281%29%2B5
1.a%2Bb=5
.
.
(2,17)
17=a%282%29%5E2%2Bb%282%29%2B5
4a%2B2b=12
2.2a%2Bb=6
Subtract eq. 1 from eq. 2,
2a%2Bb-a-b=6-5
a=1
Then from eq. 1,
1%2Bb=5
b=4