You can put this solution on YOUR website! Help me solve tan 11pi/12
tan(11π/12)=tan(8π/12+3π/12)=tan(2π/3+π/4)
Identity: tan(x+y)=(tanx+tany)/(1-tanxtany)
tanx=tan(2π/3)=-√3
tany=tan(π/4)=1
tan(11π/12)=tan(2π/3+π/4)=(-√3+1)/(1+√3*1)=(-√3+1)/(1+√3)
Check:
tan(11π/12)≈-0.2679.. (w/calculator)
exact value=(-√3+1)/(1+√3)≈-0.2679..
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