SOLUTION: A rectangle is twice as long as it is wide. If its area is 50 sq. yd., find the length. 10 yd. 25 yd. 33 yd.

Algebra ->  Rectangles -> SOLUTION: A rectangle is twice as long as it is wide. If its area is 50 sq. yd., find the length. 10 yd. 25 yd. 33 yd.      Log On


   

Question 954769: A rectangle is twice as long as it is wide. If its area is 50 sq. yd., find the length.
10 yd.
25 yd.
33 yd.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
W=width; L=length=2W;
area=L%2AW
50yd%5E2=L%2AW Substitute for L.
50yd%5E2=2W%2AW Divide each side by 2.
25yd%5E2=W%5E2 Find the square root of each side.
5yd=W The width is 5 yards.
L=2W=2(5yd)=10yd ANSWER: The length is 10 yards. The first answer is correct.