SOLUTION: find the standard equation of the parabola whose vertex (-1,-2) passing through (3,6) axis horizontal ?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find the standard equation of the parabola whose vertex (-1,-2) passing through (3,6) axis horizontal ?      Log On


   

Question 954752: find the standard equation of the parabola whose vertex (-1,-2) passing through (3,6) axis horizontal ?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
In vertex form,
x=a%28y%2B2%29%5E2-1
So then using the point,
3=a%286%2B2%29%5E2-1
4=a%2864%29%5E2
a=1%2F16
So then,
x=%28y%2B1%29%5E2%2F16-2