SOLUTION: Sketch the straight line defined by the linear equation by finding the x- and y- intercepts 5x-3y+15 =0

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Question 954460: Sketch the straight line defined by the linear equation by finding the x- and y- intercepts
5x-3y+15 =0
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
5x-3y+15 =0
x-intercept:
5x+15=0
5x=-15
x=-3
y-intercept:
-3y+15=0
-3y=-15
y=5
.
GRAPH:
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+%285%2F3%29x%2B5%29+