SOLUTION: find the lateral area and surface area of a regular hexagonal pyramid with base edge length 4 meters and slant height 8 meters

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Question 954336: find the lateral area and surface area of a regular hexagonal pyramid with base edge length 4 meters and slant height 8 meters
Answer by macston(5194) About Me  (Show Source):
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b=base edge=4m; s=slant height=8m
lateral surface area=(6)(1/2)bs=3bs=3(4m)(8m)=96 sq m
ANSWER 1: The lateral surface area is 96 square meters.
Area of base:
Area=%28%283sqrt%283%29%29%2F2%29b%5E2=2.598%284%5E2m%5E2%29=2.598%2816m%5E2%29=41.57m
The area of the base is 41.57 square meters.
Surface area=lateral area + base area=96 sq m+41.57 sq m=137.57 sq m
ANSWER 2: The surface area is 137.57 square meters.