SOLUTION: Find two consecutive integers such that the smaller integer is six more than twice the larger integer.
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Question 954313
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Find two consecutive integers such that the smaller integer is six more than twice the larger integer.
Answer by
CubeyThePenguin(3113)
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consecutive integers: x, (x+1)
x = 6 + 2(x+1)
x = 6 + 2x + 2
x = 2x + 8
-x = 8
x = -8
The integers are -8 and -7.