Question 954303: Please help me find all the solutions in this equation, the answer must be in radians:
cos2x+√3sinx=1
Thank you very much!
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Please help me find all the solutions in this equation, the answer must be in radians:
cos2x+√3sinx=1
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cos^2(x)-sin^2(x)+√3sinx=1
1-sin^2(x)-sin^2(x)+√3sinx=1
2sin^2(x)-√3sinx=0
sinx(2sinx-√3)=0
sinx=0
x=0+2πk, π+2πk, k=any integer
..
2sinx-√3=0
sinx=√3/2
x=π/3+2πk, 5π/3+2πk, k=any integer
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