SOLUTION: 1.on earth the acceleration g. due to gravity is approximately 32ft/second. using the formula v=√2gd ,what is the velocity of an object after falling 7ft from the point wher

Algebra ->  Trigonometry-basics -> SOLUTION: 1.on earth the acceleration g. due to gravity is approximately 32ft/second. using the formula v=√2gd ,what is the velocity of an object after falling 7ft from the point wher      Log On


   

Question 954123: 1.on earth the acceleration g. due to gravity is approximately 32ft/second. using the formula v=√2gd ,what is the velocity of an object after falling 7ft from the point where it was dropped?

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
g=32ft/sec^2; d=7ft; v=velocity=sqrt%282gd%29; s%5E2=seconds%5E2
v=sqrt%282gd%29
v=sqrt%282%2832ft%2Fseconds%5E2%29%287ft%29%29
v=sqrt%282%28224ft%5E2%2Fseconds%5E2%29%29
v=sqrt%28448ft%5E2%2Fseconds%5E2%29=21.2 ft/sec
ANSWER: The objects velocity 7 seconds after being dropped is 21.2 ft/sec.