Question 954069: Find three consecutive positive integers such that the square of the first, increased by the last, is 22.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Find three consecutive positive integers such that the square of the first, increased by the last, is 22.
:
Three consecutive numbers, x, (x+1), (x+2)
n^2 + (n+2) = 22
n^2 + n + 2 - 22 = 0
n^2 + n - 20 = 0
Factors to
(n+5)(n-4) = 0
The positive solution
n = 4
then
4, 5, 6 are the 3 consecutive numbers
:
:
Check this:
4^2 + 6 = 22
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