SOLUTION: Please, someone help me. I am having difficulties to find the rational zeros of p(x)=x^4+2x^3-2x^2-3x+2

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Question 953927: Please, someone help me. I am having difficulties to find the rational zeros of p(x)=x^4+2x^3-2x^2-3x+2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2Cx%5E4%2B2x%5E3-2x%5E2-3x%2B2%29
By the rational roots theorem, the possible rational roots are +/-1 and +/-2.
Looks like x=-2 and x=1 are zeros.
Plug them in to verify.
I'll do one, you do the other,
1%5E4%2B2%281%29%5E3-2%281%29%5E2-3%281%29%2B2=1%2B2-2-3%2B2=0
By the graph and the rational roots theorem, the other two roots are not rational.