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Question 953729: A chord passing through the focus of the parabola x^2= 16y has one end at pt. (12,9) where is the other end of the chord?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! A chord passing through the focus of the parabola x^2= 16y has one end at pt. (12,9) where is the other end of the chord?
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parabola opens upward with vertex at the origin (0,0)
Its basic equation: x^2=4py
4p=16
p=4
A chord passing through the focus of the parabola is the latus rectum or focal width=4p=16. It is also p or 4 units above the vertex.
so ends of the chord are (-8,4) and (8,4)
Where did the point (12,9) come from?
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