SOLUTION: "One odd number is 6 more than another odd number. The sum of the numbers is 160. What are the numbers?" This question does not ask for consecutive odd numbers. I have tried n+n+2=
Algebra ->
Problems-with-consecutive-odd-even-integers
-> SOLUTION: "One odd number is 6 more than another odd number. The sum of the numbers is 160. What are the numbers?" This question does not ask for consecutive odd numbers. I have tried n+n+2=
Log On
Question 953657: "One odd number is 6 more than another odd number. The sum of the numbers is 160. What are the numbers?" This question does not ask for consecutive odd numbers. I have tried n+n+2=160;2n=158, n=79 and n+2= 81 so adding these does give 160. However their difference is not 6. Next I tried n+n+8=160 but n=76 an even number added to 84=160 but not odd numbers which are called for. Found 2 solutions by macston, MathTherapy:Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! n=one odd number; n-6=the other odd number
n+(n-6)=160
2n=166
n=83 ANSWER: One odd number is 83.
n-6=83-6=77 ANSWER 2: The other number is 77.
CHECK:
83+77=160
160=160
The problem did not specify consecutive, but it did specify a difference of 6 (instead of 2).
You can put this solution on YOUR website!
"One odd number is 6 more than another odd number. The sum of the numbers is 160. What are the numbers?" This question does not ask for consecutive odd numbers. I have tried n+n+2=160;2n=158, n=79 and n+2= 81 so adding these does give 160. However their difference is not 6. Next I tried n+n+8=160 but n=76 an even number added to 84=160 but not odd numbers which are called for.
Where did you get “n + 2” from?
Where did you get “n + 8” from?
You seem to have “everything” except n + 6 for the LARGER number. Why is this?
Let the smaller number be S
Then larger number = S + 6
Therefore, we get: S + S + 6 = 160
2S = 160 – 6
2S = 154
S, or smaller number = , or
Larger number: 77 + 6, or
