SOLUTION: How do you write an equation in slope-intercept form of the line satisfying the given conditions find the coordinates of the midpoint of the segment whose endpoints are (-2, 14) an

Algebra ->  Functions -> SOLUTION: How do you write an equation in slope-intercept form of the line satisfying the given conditions find the coordinates of the midpoint of the segment whose endpoints are (-2, 14) an      Log On


   

Question 95363: How do you write an equation in slope-intercept form of the line satisfying the given conditions find the coordinates of the midpoint of the segment whose endpoints are (-2, 14) and (3, -9)
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
Y=mX+b IS THE LINE FORMULA WHERE (m)=SLOPE & (b)=Y INTERCEPT.
SLOPE=(Y2-Y1)/(X2-X1)
SLOPE=(-9-14)/3+2)=-23/5
NOW REPLACE THE X& Y TERMS IN THE LINE EQUATION WITH ONE SET OF POINTS.
14=-23/5*-2+b
14=46/5+b
b=14-46/5
b=(70-46)/5
b=24/5 THE Y INTERCEPT.
THUS THE LINE EQUATION IS:
Y=-23X/5+24/5
THE MID POINT IS FOUND BY:
(3+2)/2=5/2=2.5
3-2/5=.5 IS THE X MIDPOINT.
(14+9)/2=23/2=11.5
14-11.5=2.5 IS THE Y MIDPOINT.
THUS THE MIDPOINT OF THIS LINE IS (.5,2.5)
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-23x%2F5+%2B24%2F5%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -23x/5 +24/5).