SOLUTION: A circle has the equation x^2+y^2-6x+12y+9=0. Determine the distance from the center of the circle to the line y=2x+10

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: A circle has the equation x^2+y^2-6x+12y+9=0. Determine the distance from the center of the circle to the line y=2x+10      Log On


   



Question 953566: A circle has the equation x^2+y^2-6x+12y+9=0.
Determine the distance from the center of the circle to the line y=2x+10

Answer by Alan3354(69443) About Me  (Show Source):
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A circle has the equation x^2+y^2-6x+12y+9=0.
Determine the distance from the center of the circle to the line y=2x+10
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Find the center of the circle. Do you know how to do that?
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The slope of y = 2x+10 is 2.
The slope of lines perpendicular to it is -1/2
Find the eqn of the line thru the center with a slope of -1/2
Find the intersection of that line and y = 2x+10
Find the distance between the 2 points.