Question 953539: Please help!
The difference of two positive numbers is 2 and the sum of their squares is 74. Find the numbers Found 2 solutions by Alan3354, stanbon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The difference of two positive numbers is 2 and the sum of their squares is 74. Find the numbers
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x - y = 2 --> y = x - 2
x^2 + y^2 = 74
Sub for y in the 2nd eqn and solve for x, etc
x^2 + (x-2)^2 = 74
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Or, since 74 is not a big number, search for it.
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1^2 + 3^2 = 10 NG
2^2 + 4^2 = 20 NG
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5^2 + 7^2 = 74
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Was that hard?
You can put this solution on YOUR website! The difference of two positive numbers is 2 and the sum of their squares is 74. Find the numbers
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x^2 + y^2 = 74
x - y = 2
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Solve for "x"::
x = y+2
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Substitute and solve for "y"::
(y+2)^2 + y^2 = 74
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y^2 + 4y + 4 + y^2 = 74
2y^2 + 4y + 4 = 74
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Modify::
y^2 + 2y - 35 = 0
(y+7)(y-5) = 0
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Positive solution:
y = 5
x = y+2 = 7
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Cheers,
Stan H.
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