SOLUTION: What are the foci of the ellipse? Graph the ellipse. x^2/49+y^2/64=1 Foci (0,+-sqrt 15) Foci (0,+-sqrt 113)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What are the foci of the ellipse? Graph the ellipse. x^2/49+y^2/64=1 Foci (0,+-sqrt 15) Foci (0,+-sqrt 113)      Log On


   

Question 953481: What are the foci of the ellipse? Graph the ellipse.
x^2/49+y^2/64=1
Foci (0,+-sqrt 15)
Foci (0,+-sqrt 113)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E2%2F49%2By%5E2%2F64=1
a%5E2=49=>a=7
b%5E2=64=>b=8
The formula generally associated with the focus of an ellipse is b%5E2=+a%5E2+%26%238722%3B+c%5E2 where c is the distance from the focus to vertex.
b%5E2=+a%5E2+%26%238722%3B+c%5E2
64=+49+%26%238722%3B+c%5E2
c%5E2=++64-49
c%5E2=++15
c=+sqrt%28+15%29 or c=-+sqrt%28+15%29
so, answer is: Foci (0,+-sqrt 15)