SOLUTION: how to convert r^2sin2(theta)=8 from a polar equation to a rectangular equation

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Question 953419: how to convert
r^2sin2(theta)=8
from a polar equation to a rectangular equation
Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388) About Me  (Show Source):
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
convert
r^2sin2(theta)=8
from a polar equation to a rectangular equation
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Conversion form:
r = sqrt(x^2+y^2)
theta = arctan(y/x)
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Your Problem::
(x^2+y^2)*sin(2(arctan(y/x))) = 8
----
(x^2+y^2)*2sin(arctan(y/x)*cos(arctan(y/x)) = 8
----
(x^2+y^2)*2(y/sqrt(x^2+y^2))*(x/sqrt(x^2+y^2)) = 8
----
(x^2+y^2)(2(xy)/(x^2+y^2)) = 8
------
xy = 4
y = 4/x
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Cheers,
Stan H.
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