SOLUTION: the sum of three numbers is 68. the largest is 6 less than twice the smallest, and the middle number is 10 less than the largest. find the three numbers. show work

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Question 953410: the sum of three numbers is 68. the largest is 6 less than twice the smallest, and the middle number is 10 less than the largest. find the three numbers.
show work

Answer by EdenWolf(517) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the smallest number, 2x-6 = the largest number, and (2x-6)-10 = the middle number. Set up an equation.

x%2B2x-6%2B2x-6-10=68

Now solve for x.

3x-6%2B2x-6-10=68
5x-6-6-10=68
5x-12-10=68
5x-22=68
5x=90
x=18

So we have the smallest number. Now let's plug those in the other two expressions to find the other two numbers.

2x-6
2%2A18-6
36-6
30
~~~~~~~~
2x-6-10
2%2A18-6-10
36-6-10
30-10
20
So the smallest number is 18, the middle number is 20, and the largest number is 30.
Hope I helped!
~Eden