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Question 953331: alexei wants to find three consecutive integers such that three times the product of the first and last integers, decreased by 150, is equal to the square of the second integer. Which equation can Alexei use to find the integers?
a. 3x^2+12x-150=x^2+4
b. 3x^2+6x-150=x^2+2x+1
c. 3x^2+12x=x^2+14-146
d. 3x^2+6x=x^2+2x-149
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! find three consecutive integers
x, (x+1), (x+2)
:
such that three times the product of the first and last integers, decreased by 150, is equal to the square of the second integer.
3x(x+2) - 150 = (x+1)^2
distribute on the left, FOIL the right (x+1)(x+1)
3x^2 + 6x - 150 = x^2 +1x + 1x + 1
3x^2 + 6x - 150 = x^2 + 2x + 1; this looks like (b
collect like terms on the left
3x^2 - x^2 + 6x - 2x - 150 - 1 = 0
2x^2 + 4x - 151 = 0
The problem with this is the solutions are not integers
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