SOLUTION: May you please help me solve this equation:
If sin of theta equals 1/2 find cos of theta
Solve for values of theta over [pie/2 , pie]
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If sin of theta equals 1/2 find cos of theta
Solve for values of theta over [pie/2 , pie]
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Question 953264: May you please help me solve this equation:
If sin of theta equals 1/2 find cos of theta
Solve for values of theta over [pie/2 , pie] Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! If sin of theta equals 1/2 find cos of theta
Solve for values of theta over [pie/2 , pie]
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By definition, sin = y/r
So y = 1 and r = 2
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Solve for "x"::
x = sqrt[r^2-y^2] = sqrt(2^2-1^2] = sqrt(3)
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cos(t) = x/r = sqrt(3)/2
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Cheers,
Stan H.
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