SOLUTION: Find the area of a circle in which a chord AB is 48 cm and the perpendicular bisector of the chord, originating at the centre of the circle, is 10 cm.

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Question 953020: Find the area of a circle in which a chord AB is 48 cm and the perpendicular bisector of the chord, originating at the centre of the circle, is 10 cm.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
The perpendicular bisector and 1/2 of the chord are legs of a right triangle with the radius of the circle as hypotenuse, so:
r%5E2=10cm%5E2%2B%28%281%2F2%2948cm%29%5E2
r%5E2=%28100cm%5E2%29%2B%2824cm%29%5E2
r%5E2=%28100cm%5E2%29%2B%28576cm%5E2%29
r%5E2=676cm%5E2
Area=pi%28r%5E2%29=%28676cm%5E2%29pi