SOLUTION: There were 12 more nickles than dimes, and the total value of the coins was $5.10. How many nickles and dimes were there?

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Question 952962: There were 12 more nickles than dimes, and the total value of the coins was $5.10. How many nickles and dimes were there?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
d=number of dimes; n=number of nickels=d+12
$0.10d+$0.05n=$5.10 Substitute for n.
$0.10d+$0.05(d+12)=$5.10
$0.10d+$0.05(d)+$0.60=$5.10 Subtract $0.60 from each side.
$0.15d=$4.50 Divide each side by $0.15
d=30 ANSWER 1: There were 30 dimes.
n=d+12=30+12=42 ANSWER 2: There were 42 nickels.
CHECK:
$0.10(30)+$0.05(42)=$5.10
$3.00+$2.10=$5.10
$5.10=$5.10