SOLUTION: Find four consecutive even integers such that twice the sum of the second and third exceeds 3 times the first by 32.

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Question 952472: Find four consecutive even integers such that twice the sum of the second and third exceeds 3 times the first by 32.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
first=x; second=x+2; third=x+4; fourth=x+6
2((x+2)+(x+4))=3(x)+32
2(2x+6)=3x+32
4x+12=3x+32
x=20 ANSWER 1: The first integer is 20.
x+2=22 ANSWER 2: The second integer is 22.
x+4=24 ANSWER 3: The third integer is 24.
x+6=26 ANSWER 4: The fourth integer is 26.
CHECK:
2(22+24)=3(20)+32
2(46)=60+32
92=92