SOLUTION: a restaurant offers 5 appetizers, 6 entrees, and 3 desserts. how many different ways can a customer choose one appetizer, one entree, and one dessert?
Algebra ->
Permutations
-> SOLUTION: a restaurant offers 5 appetizers, 6 entrees, and 3 desserts. how many different ways can a customer choose one appetizer, one entree, and one dessert?
Log On
Question 952372: a restaurant offers 5 appetizers, 6 entrees, and 3 desserts. how many different ways can a customer choose one appetizer, one entree, and one dessert? Answer by Edwin McCravy(20056) (Show Source):
He can choose an appetizer 5 ways.
For each of those 5 ways to choose an appetizer,
he can choose an entree 6 ways.
That's 5*6 = 30 ways he can choose an appetizer and an entree.
For each of those 30 ways to choose an appetizer and an entree,
he can choose a dessert 3 ways.
That's 30*3 = 90 ways he can choose an appetizer, an entree,
and a dessert.
Answer and how to get it: 5*6*3 = 90 ways.
Edwin