SOLUTION: I am in pre-cal, but none of my previous classes mentioned general form, and my book doesn't say how to get it from any two points not intercepts. Help? Please? The points for the

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Question 95220This question is from textbook Precalculus with limits
: I am in pre-cal, but none of my previous classes mentioned general form, and my book doesn't say how to get it from any two points not intercepts. Help? Please?
The points for the problem are (-8,1) and (-8,7).
This question is from textbook Precalculus with limits

Found 3 solutions by scott8148, edjones, chitra:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the general form for a linear equation is Ax+By+C=0 where A, B, and C are integers

because the y values of the points are different but the x values are the same, the slope of the line is undefined (vertical)

the equation is x+8=0 ... the y value has no effect

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
(-8,1) and (-8,7)
General Form: Ax+By+C=0
slope-intercept form: y=mx+b
1st we get the slope (m)
m=%28y-y%5B1%5D%29%2F%28x-x%5B1%5D%29
m=(1-7)/-8+8
m=-6/0=undefined because division is not allowed.
We have to stop there.
We can't write an equation without the slope.

Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
The two point form of an equation is given by:

%28y+-+y1%29%2F%28y2+-+y1%29 = %28x+-+x1%29%2F%28x2+-+x1%29


Substituting for the points, (x1, y1) and (x2, y2) that is (-8, 1) and (-8, 7) we get:


%28y+-+1%29%2F%287+-+1%29 = %28x+-+%28-8%29%29%2F%28-8+-%28-8%29%29


%28y+-+1%29%2F%288%29 = %28%28x+%2B+8%29%2F%280%29%29


%28y+-+1%29%2F8 = 0


==> y - 1 = 0


Thus the solution...

Regards

you can get back to me on any help in pre-cal I'll surely help you online.. at any time of yours..
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