Question 952162:  2sin(x)cos(x) + sin(x)=0 
Find all angles in radians that satisfy the equation. For each solution enter first the angle solution in [0,2\pi) then the period. When 2 or more solutions are available enter them in increasing order of the angles. (e.g. x=\pi/2 +2k\pi or x=3\pi/2 +2k\pi etc.)  
Note: You are not allowed to use decimals in your answer. 
 Answer by lwsshak3(11628)      (Show Source): 
You can  put this solution on YOUR website! 2sin(x)cos(x) + sin(x)=0 
Find all angles in radians that satisfy the equation. For each solution enter first the angle solution in [0,2\pi) then the period. When 2 or more solutions are available enter them in increasing order of the angles. (e.g. x=\pi/2 +2k\pi or x=3\pi/2 +2k\pi etc.)  
Note: You are not allowed to use decimals in your answer. 
*** 
2sin(x)cos(x) + sin(x)=0 
sin(x)(2cos(x)+1)=0 
sinx=0 
x=0+πk, k=any integer 
.. 
2cos(x)+1=0 
cos(x)=-1/2 
x=2π/3+2πk, 4π/3+2πk, k= any integer 
  | 
 
  
 
 |   
 
 |