SOLUTION: when asked how many pennies she had, a collector said: If I arrange them in attacks of 5, none are left over. If I arrange then in stacks of 6, none are left over. If I arr

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: when asked how many pennies she had, a collector said: If I arrange them in attacks of 5, none are left over. If I arrange then in stacks of 6, none are left over. If I arr      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 952042: when asked how many pennies she had, a collector said:
If I arrange them in attacks of 5, none are left over.
If I arrange then in stacks of 6, none are left over.
If I arrange them in stacks of 7, one is left over.
what is the least number of coins she could have? explain your answer
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
Since we're looking for least, let's start at the beginning.
We know that it will be a multiple of 5 and 6. 5*6=30, so a multiple of 30.
30,60,90,120,150,180,210
Does 7 go into any of those with 1 remainder?
30/7 = 4 r 2
60/7 = 9 r 4
90/7 = 12 r 6
120/7 = 17 r 1