SOLUTION: A cyclist bikes at a contest speed for 18 miles. He then returns home at the same speed. His return trip takes one hour longer and is 23 miles. Find his speed.
A) 6mph B
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Polynomials-and-rational-expressions
-> SOLUTION: A cyclist bikes at a contest speed for 18 miles. He then returns home at the same speed. His return trip takes one hour longer and is 23 miles. Find his speed.
A) 6mph B
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Question 95203: A cyclist bikes at a contest speed for 18 miles. He then returns home at the same speed. His return trip takes one hour longer and is 23 miles. Find his speed.
You can put this solution on YOUR website! A cyclist bikes at a constant speed for 18 miles. He then returns home at the same speed. His return trip takes one hour longer and is 23 miles. Find his speed.
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Going DATA:
Distance = 18 miles; Rate = x mph ; Time = d/r = 18/x hrs.
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Returning DATA:
Distance = 23 miles; Rate = x mph ; Time = d/r = 23/x hrs
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EQUATION:
Going Time = Return Time -1
18/x = 23/x -1
18 = 23 - x
x = 5 mph
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Cheers,
Stan H.
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