Question 952022: (a) Solve the equation on the given interval, expressing the solution for x in terms of inverse trigonometric functions. (Enter your answers as a comma-separated list.)
10(cos x)^2 − cos x − 9 = 0 on [π/2, π]
Answer: x =
(b) Use a calculator to approximate the solution in part (a) to three decimal places. (Enter your answers as a comma-separated list.)
Answer: x =
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! (a) Solve the equation on the given interval, expressing the solution for x in terms of inverse trigonometric functions. (Enter your answers as a comma-separated list.)
10(cos x)^2 − cos x − 9 = 0 on [π/2, π]
10cos^2(x)-cosx-9=0
(10cosx+9)(cosx-1)
10cosx+9=0
cosx=-9/10
x≈2.690
cosx-1=0
cosx=1
no solution, not in given domain
Answer: x ≈2.690 radians
(b) Use a calculator to approximate the solution in part (a) to three decimal places. (Enter your answers as a comma-separated list.)
Answer: x =2.690 radians
|
|
|
