SOLUTION: Determine whether the linear system has one solution, no solution, of infinitely many solutions. 3x + y = 12 y = 3x + 12

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Determine whether the linear system has one solution, no solution, of infinitely many solutions. 3x + y = 12 y = 3x + 12      Log On


   

Question 952013: Determine whether the linear system has one solution, no solution, of infinitely many solutions.
3x + y = 12
y = 3x + 12
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
3x+%2B+y+=+12...eq.1
y+=+3x+%2B+12...eq.2
--------------------------substitute y from eq.2 in eq.1
3x+%2B+3x+%2B+12=+12...eq.1...solve for x
6x=+12-12
6x=+0
highlight%28x=0%29
y+=+3x+%2B+12...eq.2...substitute 0 for x
y+=+3%2A0+%2B+12
highlight%28y+=+12%29
the linear system has one solution, and intersection point is: (0,12)

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+15%2C+3x+%2B+12%2C+-3x+%2B+12%29+