SOLUTION: How much pure alcohol must be added to a mixture of 12 liters of alcohol and 30 liters of water to produce a 60% alcohol solution.

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Question 951658: How much pure alcohol must be added to a mixture of 12 liters of alcohol and 30 liters of water to produce a 60% alcohol solution.
Answer by macston(5194) About Me  (Show Source):
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A 60% alcohol solution would be 40% water. 30 liters of water is 40% of (30l/0.40)=75 liters, so to make a total of 75 liters we need the original 42 liters plus an additional 33 liters of alcohol. ANSWER: 33 liters of alcohol must be added.