Question 951647: A chemistry student was asked to make 100 L of 48% alcohol solution by volume by mixing 40% alcohol solution by volume and 60% alcohol solution by volume. How many litres of each must the student use?
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! Let's call the 40% solution "a" and the 60% solution "b".
a + b = 100L Therefore, a= 100 - b
.4a + .6b = .48(100) Substitute with above information:
.4(100 - b) + .6b = .48(100) Simplify:
40 - .4b + .6b = 48 Subtract 40, both sides, and add on the left:
.2b = 8 Divide both sides by .2:
b = 40 At the beginning I said let's call the 60% solution b, and now we know that b= 40, and since we said that a = 100 - b, a= 100 - 40 = 60
Answer:
You need 60 liters of the 40% solution, and
you need 40 liters of the 60% solution
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