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| Question 951605:  If sinθ = (sqrt(7)/4) and, cos < 0.
 What is tanθ?
 1) (4/3)
 2) -(sqrt(7)/4)
 3) (sqrt(7)/3)
 4) -(sqrt(7)/3)
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! If sinθ = (sqrt(7)/4) and, cos < 0. What is tanθ?
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 Note: Since sin is positive and cos is negative, theta is in QII
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 By definition sin = y/4, so y = sqrt(7), r = 4
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 The x = -sqrt[16-7] = -sqrt(9) = -3
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 Ans: tan(t) = y/x = -sqrt(7)/3
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 Cheers,
 Stan H.
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 1) (4/3)
 2) -(sqrt(7)/4)
 3) (sqrt(7)/3)
 4) -(sqrt(7)/3)
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