SOLUTION: Jane leaves her house and drives in a straight line at a speed of 30 mph. Her speed on the return trip is 40 mph. The trip back home takes 16 minutes less than the outbound trip. W

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Question 951429: Jane leaves her house and drives in a straight line at a speed of 30 mph. Her speed on the return trip is 40 mph. The trip back home takes 16 minutes less than the outbound trip. What was Jane's total travel time in hours? Assume both trips are in a straight line. Give your final answer as a simplified fraction.

Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
VARIABLES ASSIGNMENTS
r, outbound rate
R, return rate
t, time spent for "going" outbound
k, how many fewer minutes for return trip than outbound
d, one-way trip distance

QUESTION: Find total travel time.

____________________rate____________time___________distance
GOING_______________r________________t______________d
RETRNG______________R_______________t-k/60__________d

KNOWN VALUES
r=30
R=40
k=16


UNKNOWN VALUES
t, d.


SOLVE

system%28rt=d%2CR%28t-k%2F60%29=d%29
rt=R%28t-k%2F60%29
rt=Rt-kR%2F60
rt-Rt=-kR%2F60
Rt-rt=kR%2F60
t%28R-r%29=kR%2F60
highlight%28t=kR%2F%2860%28R-r%29%29%29, being reminded that k needs to be a quantity in MINUTES. t will be in hours.

Evaluate t, and then find highlight_green%28t%2B%28t-k%2F60%29%29.