SOLUTION: 1.
A right triangle has a leg that measures 19 cm and a hypotenuse that measures 48 cm. Find the length of the missing leg to the nearest tenth.
(1 point)
44.1 cm
51
Algebra ->
Triangles
-> SOLUTION: 1.
A right triangle has a leg that measures 19 cm and a hypotenuse that measures 48 cm. Find the length of the missing leg to the nearest tenth.
(1 point)
44.1 cm
51
Log On
Question 951401: 1.
A right triangle has a leg that measures 19 cm and a hypotenuse that measures 48 cm. Find the length of the missing leg to the nearest tenth.
(1 point)
44.1 cm
51.6 cm
66.2 cm
29 cm
2. In a 30-60-90 triangle, the hypotenuse measures 28 inches. What is the length of the short leg?
(1 point)
9 inches
14 inches
20 inches
cannot be determined from the information
3. A square has a diagonal that measures 50 inches. Find the area of the square.
(1 point)
625 square inches
2500 square inches
1250 square inches
100 square inches
4. Which of the following is NOT a "special" right triangle?
(1 point)
isosceles right
20-70-90
30-60-90
45-45-90
5. Find the perimeter of a right triangle that has a leg that measures 36 m and another leg that measures 15 m.
(1 point)
51 m
90 m
65 m
75 m
You can put this solution on YOUR website! A right triangle has a leg that measures 19 cm and a hypotenuse that measures 48 cm. Find the length of the missing leg to the nearest tenth.
----
leg = sqrt[48^2-19^2] = sqrt(1943) = 44.08..
-----------------
2. In a 30-60-90 triangle, the hypotenuse measures 28 inches. What is the length of the short leg?
-----
If shortest is 1, the hypotenuse is 2, and the other leg is sqrt(3)
So, if hypo = 28, shortest = (1/2)28 = 14 inches
------------------
3. A square has a diagonal that measures 50 inches. Find the area of the square.
Area = side^2
If diagonal = 50, side = 50/sqrt(2)
Then area = (50/sqrt(2)^2 = 2500/2 = 1250 sq inches
-----------------------
4. Which of the following is NOT a "special" right triangle?
(1 point)
Ans: 20-70-90
-----------------------------
5. Find the perimeter of a right triangle that has a leg that measures 36 m and another leg that measures 15 m.
Hypotenuse = sqrt[36^2+15^2] = sqrt(1552
H = 39.4..
------------
Cheers,
Stan H.
---------
PROBLEM 2:
In a 30-60-90 triangle, hypotenuse is twice shortest side
hypotenuse/2=shortest leg
28 in/2=14 in ANSWER The shortest leg is 14 inches.
PROBLEM 3:
d=diagonal; A=area=
A=1250 sq in ANSWER: The area of the square is 1250 sq in.
PROBLEM 4:
ANSWER: 20-70-90 is not a "special" right triangle.
PROBLEM 5:
Perimeter=a+b+c
Perimeter=15m+36m+39m
Perimeter=90m ANSWER: The perimeter of the triangle is 90 meters.