SOLUTION: Differentiate the function : f(x) = x^-1+x^0,5.

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Question 951370: Differentiate the function : f(x) = x^-1+x^0,5.
Found 3 solutions by stanbon, Fombitz, Alan3354:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Differentiate the function : f(x) = x^-1+x^0,5.
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f'(x) = -x^-2 + 0.5x^-0.5
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f'(x) = -(1/x^2) + 0.5/sqrt(x)
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Cheers,
Stan H.
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Answer by Fombitz(32388) About Me  (Show Source):
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = x^-1 + x^0.5
f'(x) = -x%5E-2+%2B+0.5x%5E-0.5
= 1%2F%282sqrt%28x%29%29+-+1%2Fx%5E2
= x%2Asqrt%28x%29%2F%282x%5E2%29+-+1%2Fx%5E2
= %28x%2Asqrt%28x%29+-+2%29%2F2x%5E2