SOLUTION: One side of a rectangle is 2 times the other, and the perimeter is not to exceed 72. Find the possible values for x, the length of the shorter side. x>=24 0<x<=12 x<=12

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Question 951349: One side of a rectangle is 2 times the other, and the perimeter is not to exceed 72. Find the possible values for x, the length of the shorter side.

x>=24
0 x<=12
0
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

One side of a rectangle x is 2 times the other, then the other side is 2x,
and the perimeter P is not to exceed 72, then
P%3C=72
P=2%2Ax%2B2%2A2x
P=2x%2B4x
P=6x
and, since P%3C=72 , then
6x%3C=72...solve for x}
x%3C=72%2F6
x%3C=12
find 2x

2x%3C=2%2A12
2x%3C=24

solution set:
0%3Cx%3C=24