Question 951278: The length of a rectangle is 2 feet more than 5 times the width. If the area is 51 square feet, find the width and the length.
Answer by sophxmai(62)   (Show Source):
You can put this solution on YOUR website! The length of a rectangle is 2 feet more than 5 times the width. If the area is 51 square feet, find the width and the length.
Area of a rectangle is the length times the width.
Let width=x
If the length is 2 feet more than 5 times the width, then let length=5x+2
From the question, the area=51
So,
A=wl
A=x(5x+2)
51=x(5x+2)
Now solve for x
51=x(5x+2)
51=5x^2+2x
0=5x^2+2x-51
0=(5x+17)(x-3)
x=-17/5, x=3
Since the width of a rectangle can't be negative, we can disregard that solution and thus x, the width=3
and if the length is 2 more than 5 times the width, the length would be 17
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