SOLUTION: If prison terms for possession of marijuana is normally distributed with a mean of 41 months and a standard deviation of 12 months what is the probability that a randomly selected

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Question 951194: If prison terms for possession of marijuana is normally distributed with a mean of 41 months and a standard deviation of 12 months what is the probability that a randomly selected offender will have been sentenced between 41 and 61 months?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Find the z score for both times,
z%5B1%5D=%2841-41%29%2F12=0
z%5B2%5D=%2861-41%29%2F12=1.67
Then the probability would be,
P=P%28z%5B2%5D%29-P%28z%5B1%5D%29
P=0.95221-0.5
P=0.452