SOLUTION: Which is the factored form of x3 + 6x2 - 25x + 18 = 0? A. (x + 1)(x - 3)(x - 6) = 0 B. (x + 1)(x - 2)(x + 9) = 0 C. (x - 1)(x - 3)(x - 6) = 0

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Which is the factored form of x3 + 6x2 - 25x + 18 = 0? A. (x + 1)(x - 3)(x - 6) = 0 B. (x + 1)(x - 2)(x + 9) = 0 C. (x - 1)(x - 3)(x - 6) = 0       Log On


   

Question 951182: Which is the factored form of x3 + 6x2 - 25x + 18 = 0?

A. (x + 1)(x - 3)(x - 6) = 0
B. (x + 1)(x - 2)(x + 9) = 0
C. (x - 1)(x - 3)(x - 6) = 0
D. (x - 1)(x - 2)(x + 9) = 0
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
x^3 + 6x^2 - 25x + 18 = 0 ...factor completely; write 6x%5E2 as 8x%5E2-2x%5E2, and -+25x as -+9x-16x
x%5E3%2B8x%5E2-9x-2x%5E2-16x%2B18 group
%28x%5E3-2x%5E2%29%2B%288x%5E2-16x%29-%289x-18%29
x%5E2%28x-2%29%2B8x%28x-2%29-9%28x-2%29
%28x-2%29+%28x%5E2%2B8x-9%29=0
%28x-2%29+%28x%5E2-x%2B9x-9%29=0
%28x-2%29+%28%28x%5E2-x%29%2B%289x-9%29%29=0
%28x-2%29+%28x%28x-1%29%2B9%28x-1%29%29=0
%28x-2%29+%28x-1%29+%28x%2B9%29+=+0

answer is:
D. %28x+-+1%29%28x+-+2%29%28x+%2B+9%29+=+0